(x-7)(x^2+4x+5)=0

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Solution for (x-7)(x^2+4x+5)=0 equation:


Simplifying
(x + -7)(x2 + 4x + 5) = 0

Reorder the terms:
(-7 + x)(x2 + 4x + 5) = 0

Reorder the terms:
(-7 + x)(5 + 4x + x2) = 0

Multiply (-7 + x) * (5 + 4x + x2)
(-7(5 + 4x + x2) + x(5 + 4x + x2)) = 0
((5 * -7 + 4x * -7 + x2 * -7) + x(5 + 4x + x2)) = 0
((-35 + -28x + -7x2) + x(5 + 4x + x2)) = 0
(-35 + -28x + -7x2 + (5 * x + 4x * x + x2 * x)) = 0
(-35 + -28x + -7x2 + (5x + 4x2 + x3)) = 0

Reorder the terms:
(-35 + -28x + 5x + -7x2 + 4x2 + x3) = 0

Combine like terms: -28x + 5x = -23x
(-35 + -23x + -7x2 + 4x2 + x3) = 0

Combine like terms: -7x2 + 4x2 = -3x2
(-35 + -23x + -3x2 + x3) = 0

Solving
-35 + -23x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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